Isomorphism: Isomorphism and Embedding
module plfa.part1.Isomorphism where
This section introduces isomorphism as a way of asserting that two types are equal, and embedding as a way of asserting that one type is smaller than another. We apply isomorphisms in the next chapter to demonstrate that operations on types such as product and sum satisfy properties akin to associativity, commutativity, and distributivity.
Imports
import Relation.Binary.PropositionalEquality as Eq open Eq using (_≡_; refl; cong; cong-app) open Eq.≡-Reasoning open import Data.Nat.Base using (ℕ; zero; suc; _+_) open import Data.Nat.Properties using (+-comm)
Lambda expressions
The chapter begins with a few preliminaries that will be useful here and elsewhere: lambda expressions, function composition, and extensionality.
Lambda expressions provide a compact way to define functions without naming them. A term of the form
λ{ P₁ → N₁; ⋯ ; Pₙ → Nₙ }
is equivalent to a function f
defined by the equations
f P₁ = N₁
⋯
f Pₙ = Nₙ
where the Pₙ
are patterns (left-hand sides of an equation) and the Nₙ
are expressions (right-hand side of an equation).
In the case that there is one equation and the pattern is a variable, we may also use the syntax
λ x → N
or
λ (x : A) → N
both of which are equivalent to λ{x → N}
. The latter allows one to specify the domain of the function.
Often using an anonymous lambda expression is more convenient than using a named function: it avoids a lengthy type declaration; and the definition appears exactly where the function is used, so there is no need for the writer to remember to declare it in advance, or for the reader to search for the definition in the code.
Function composition
In what follows, we will make use of function composition:_∘_ : ∀ {A B C : Set} → (B → C) → (A → B) → (A → C) (g ∘ f) x = g (f x)Thus,
g ∘ f
is the function that first applies f
and then applies g
. An equivalent definition, exploiting lambda expressions, is as follows:_∘′_ : ∀ {A B C : Set} → (B → C) → (A → B) → (A → C) g ∘′ f = λ x → g (f x)
Extensionality
Extensionality asserts that the only way to distinguish functions is by applying them; if two functions applied to the same argument always yield the same result, then they are the same function. It is the converse of cong-app
, as introduced earlier.
postulate extensionality : ∀ {A B : Set} {f g : A → B} → (∀ (x : A) → f x ≡ g x) ----------------------- → f ≡ g
Postulating extensionality does not lead to difficulties, as it is known to be consistent with the theory that underlies Agda.
As an example, consider that we need results from two libraries, one where addition is defined, as in Chapter Naturals, and one where it is defined the other way around._+′_ : ℕ → ℕ → ℕ m +′ zero = m m +′ suc n = suc (m +′ n)Applying commutativity, it is easy to show that both operators always return the same result given the same arguments:
same-app : ∀ (m n : ℕ) → m +′ n ≡ m + n same-app m n rewrite +-comm m n = helper m n where helper : ∀ (m n : ℕ) → m +′ n ≡ n + m helper m zero = refl helper m (suc n) = cong suc (helper m n)However, it might be convenient to assert that the two operators are actually indistinguishable. This we can do via two applications of extensionality:
same : _+′_ ≡ _+_ same = extensionality (λ m → extensionality (λ n → same-app m n))
We occasionally need to postulate extensionality in what follows.
More generally, we may wish to postulate extensionality for dependent functions.postulate ∀-extensionality : ∀ {A : Set} {B : A → Set} {f g : ∀(x : A) → B x} → (∀ (x : A) → f x ≡ g x) ----------------------- → f ≡ g
Here the type of f
and g
has changed from A → B
to ∀ (x : A) → B x
, generalising ordinary functions to dependent functions.
Isomorphism
Two sets are isomorphic if they are in one-to-one correspondence. Here is a formal definition of isomorphism:infix 0 _≃_ record _≃_ (A B : Set) : Set where field to : A → B from : B → A from∘to : ∀ (x : A) → from (to x) ≡ x to∘from : ∀ (y : B) → to (from y) ≡ y open _≃_
Let’s unpack the definition. An isomorphism between sets A
and B
consists of four things:
- A function
to
fromA
toB
, - A function
from
fromB
back toA
, - Evidence
from∘to
asserting thatfrom
is a left-inverse forto
, - Evidence
to∘from
asserting thatfrom
is a right-inverse forto
.
In particular, the third asserts that from ∘ to
is the identity, and the fourth that to ∘ from
is the identity, hence the names. The declaration open _≃_
makes available the names to
, from
, from∘to
, and to∘from
, otherwise we would need to write _≃_.to
and so on.
data _≃′_ (A B : Set): Set where mk-≃′ : ∀ (to : A → B) → ∀ (from : B → A) → ∀ (from∘to : (∀ (x : A) → from (to x) ≡ x)) → ∀ (to∘from : (∀ (y : B) → to (from y) ≡ y)) → A ≃′ B to′ : ∀ {A B : Set} → (A ≃′ B) → (A → B) to′ (mk-≃′ f g g∘f f∘g) = f from′ : ∀ {A B : Set} → (A ≃′ B) → (B → A) from′ (mk-≃′ f g g∘f f∘g) = g from∘to′ : ∀ {A B : Set} → (A≃B : A ≃′ B) → (∀ (x : A) → from′ A≃B (to′ A≃B x) ≡ x) from∘to′ (mk-≃′ f g g∘f f∘g) = g∘f to∘from′ : ∀ {A B : Set} → (A≃B : A ≃′ B) → (∀ (y : B) → to′ A≃B (from′ A≃B y) ≡ y) to∘from′ (mk-≃′ f g g∘f f∘g) = f∘g
We construct values of the record type with the syntax
record
{ to = f
; from = g
; from∘to = g∘f
; to∘from = f∘g
}
which corresponds to using the constructor of the corresponding inductive type
mk-≃′ f g g∘f f∘g
where f
, g
, g∘f
, and f∘g
are values of suitable types.
Isomorphism is an equivalence
Isomorphism is an equivalence, meaning that it is reflexive, symmetric, and transitive. To show isomorphism is reflexive, we take bothto
and from
to be the identity function:≃-refl : ∀ {A : Set} ----- → A ≃ A ≃-refl = record { to = λ{x → x} ; from = λ{y → y} ; from∘to = λ{x → refl} ; to∘from = λ{y → refl} }
In the above, to
and from
are both bound to identity functions, and from∘to
and to∘from
are both bound to functions that discard their argument and return refl
. In this case, refl
alone is an adequate proof since for the left inverse, from (to x)
simplifies to x
, and similarly for the right inverse.
to
and from
, and from∘to
and to∘from
:≃-sym : ∀ {A B : Set} → A ≃ B ----- → B ≃ A ≃-sym A≃B = record { to = from A≃B ; from = to A≃B ; from∘to = to∘from A≃B ; to∘from = from∘to A≃B }To show isomorphism is transitive, we compose the
to
and from
functions, and use equational reasoning to combine the inverses:≃-trans : ∀ {A B C : Set} → A ≃ B → B ≃ C ----- → A ≃ C ≃-trans A≃B B≃C = record { to = to B≃C ∘ to A≃B ; from = from A≃B ∘ from B≃C ; from∘to = λ{x → begin (from A≃B ∘ from B≃C) ((to B≃C ∘ to A≃B) x) ≡⟨⟩ from A≃B (from B≃C (to B≃C (to A≃B x))) ≡⟨ cong (from A≃B) (from∘to B≃C (to A≃B x)) ⟩ from A≃B (to A≃B x) ≡⟨ from∘to A≃B x ⟩ x ∎} ; to∘from = λ{y → begin (to B≃C ∘ to A≃B) ((from A≃B ∘ from B≃C) y) ≡⟨⟩ to B≃C (to A≃B (from A≃B (from B≃C y))) ≡⟨ cong (to B≃C) (to∘from A≃B (from B≃C y)) ⟩ to B≃C (from B≃C y) ≡⟨ to∘from B≃C y ⟩ y ∎} }
Equational reasoning for isomorphism
It is straightforward to support a variant of equational reasoning for isomorphism. We essentially copy the previous definition of equality for isomorphism. We omit the form that corresponds to _≡⟨⟩_
, since trivial isomorphisms arise far less often than trivial equalities:
module ≃-Reasoning where infix 1 ≃-begin_ infixr 2 _≃⟨_⟩_ infix 3 _≃-∎ ≃-begin_ : ∀ {A B : Set} → A ≃ B ----- → A ≃ B ≃-begin A≃B = A≃B _≃⟨_⟩_ : ∀ (A : Set) {B C : Set} → A ≃ B → B ≃ C ----- → A ≃ C A ≃⟨ A≃B ⟩ B≃C = ≃-trans A≃B B≃C _≃-∎ : ∀ (A : Set) ----- → A ≃ A A ≃-∎ = ≃-refl open ≃-Reasoning
Embedding
We also need the notion of embedding, which is a weakening of isomorphism. While an isomorphism shows that two types are in one-to-one correspondence, an embedding shows that the first type is included in the second; or, equivalently, that there is a many-to-one correspondence between the second type and the first.
Here is the formal definition of embedding:infix 0 _≲_ record _≲_ (A B : Set) : Set where field to : A → B from : B → A from∘to : ∀ (x : A) → from (to x) ≡ x open _≲_
It is the same as an isomorphism, save that it lacks the to∘from
field. Hence, we know that from
is left-inverse to to
, but not that from
is right-inverse to to
.
≲-refl : ∀ {A : Set} → A ≲ A ≲-refl = record { to = λ{x → x} ; from = λ{y → y} ; from∘to = λ{x → refl} } ≲-trans : ∀ {A B C : Set} → A ≲ B → B ≲ C → A ≲ C ≲-trans A≲B B≲C = record { to = λ{x → to B≲C (to A≲B x)} ; from = λ{y → from A≲B (from B≲C y)} ; from∘to = λ{x → begin from A≲B (from B≲C (to B≲C (to A≲B x))) ≡⟨ cong (from A≲B) (from∘to B≲C (to A≲B x)) ⟩ from A≲B (to A≲B x) ≡⟨ from∘to A≲B x ⟩ x ∎} }It is also easy to see that if two types embed in each other, and the embedding functions correspond, then they are isomorphic. This is a weak form of anti-symmetry:
≲-antisym : ∀ {A B : Set} → (A≲B : A ≲ B) → (B≲A : B ≲ A) → (to A≲B ≡ from B≲A) → (from A≲B ≡ to B≲A) ------------------- → A ≃ B ≲-antisym A≲B B≲A to≡from from≡to = record { to = to A≲B ; from = from A≲B ; from∘to = from∘to A≲B ; to∘from = λ{y → begin to A≲B (from A≲B y) ≡⟨ cong (to A≲B) (cong-app from≡to y) ⟩ to A≲B (to B≲A y) ≡⟨ cong-app to≡from (to B≲A y) ⟩ from B≲A (to B≲A y) ≡⟨ from∘to B≲A y ⟩ y ∎} }
The first three components are copied from the embedding, while the last combines the left inverse of B ≲ A
with the equivalences of the to
and from
components from the two embeddings to obtain the right inverse of the isomorphism.
Equational reasoning for embedding
We can also support tabular reasoning for embedding, analogous to that used for isomorphism:
module ≲-Reasoning where infix 1 ≲-begin_ infixr 2 _≲⟨_⟩_ infix 3 _≲-∎ ≲-begin_ : ∀ {A B : Set} → A ≲ B ----- → A ≲ B ≲-begin A≲B = A≲B _≲⟨_⟩_ : ∀ (A : Set) {B C : Set} → A ≲ B → B ≲ C ----- → A ≲ C A ≲⟨ A≲B ⟩ B≲C = ≲-trans A≲B B≲C _≲-∎ : ∀ (A : Set) ----- → A ≲ A A ≲-∎ = ≲-refl open ≲-Reasoning
Exercise ≃-implies-≲
(practice)
Show that every isomorphism implies an embedding.postulate ≃-implies-≲ : ∀ {A B : Set} → A ≃ B ----- → A ≲ B
-- Your code goes here
Exercise _⇔_
(practice)
Define equivalence of propositions (also known as “if and only if”) as follows:record _⇔_ (A B : Set) : Set where field to : A → B from : B → A
Show that equivalence is reflexive, symmetric, and transitive.
-- Your code goes here
Exercise Bin-embedding
(stretch)
Recall that Exercises Bin and Bin-laws define a datatype Bin
of bitstrings representing natural numbers, and asks you to define the following functions and predicates:
to : ℕ → Bin
from : Bin → ℕ
which satisfy the following property:
from (to n) ≡ n
Using the above, establish that there is an embedding of ℕ
into Bin
.-- Your code goes here
Why do to
and from
not form an isomorphism?
Standard library
Definitions similar to those in this chapter can be found in the standard library:import Function.Base using (_∘_) import Function.Bundles using (_↔_; _↩_)
The standard library _↔︎_
and _↩︎_
correspond to our _≃_
and _≲_
, respectively, but those in the standard library are less convenient, since they depend on a nested record structure and are parameterised with regard to an arbitrary notion of equivalence.
Unicode
This chapter uses the following unicode:
∘ U+2218 RING OPERATOR (\o, \circ, \comp)
λ U+03BB GREEK SMALL LETTER LAMBDA (\lambda, \Gl)
≃ U+2243 ASYMPTOTICALLY EQUAL TO (\~-)
≲ U+2272 LESS-THAN OR EQUIVALENT TO (\<~)
⇔ U+21D4 LEFT RIGHT DOUBLE ARROW (\<=>)